Error en que los numeros de boletas eran comparados segun sus valor ascii y no de forma natural

Se agrego una clase de otra persona que hace el trabajo, gracias buen hombre <3
This commit is contained in:
Daniel Cortes
2019-01-12 18:11:22 -03:00
parent 06b2de9f65
commit 3b6baf3bed
4 changed files with 283 additions and 57 deletions

View File

@@ -0,0 +1,128 @@
/*
NaturalOrderComparator.java -- Perform 'natural order' comparisons of strings in Java.
Copyright (C) 2003 by Pierre-Luc Paour <natorder@paour.com>
Based on the C version by Martin Pool, of which this is more or less a straight conversion.
Copyright (C) 2000 by Martin Pool <mbp@humbug.org.au>
This software is provided 'as-is', without any express or implied
warranty. In no event will the authors be held liable for any damages
arising from the use of this software.
Permission is granted to anyone to use this software for any purpose,
including commercial applications, and to alter it and redistribute it
freely, subject to the following restrictions:
1. The origin of this software must not be misrepresented; you must not
claim that you wrote the original software. If you use this software
in a product, an acknowledgment in the product documentation would be
appreciated but is not required.
2. Altered source versions must be plainly marked as such, and must not be
misrepresented as being the original software.
3. This notice may not be removed or altered from any source distribution.
This class was sightly modified by Daniel Cortes, removing the main method that it had
*/
package danielcortes.xyz.utils;
import java.util.*;
public class NaturalOrderComparator implements Comparator {
int compareRight(String a, String b) {
int bias = 0, ia = 0, ib = 0;
// The longest run of digits wins. That aside, the greatest
// value wins, but we can't know that it will until we've scanned
// both numbers to know that they have the same magnitude, so we
// remember it in BIAS.
for (; ; ia++, ib++) {
char ca = charAt(a, ia);
char cb = charAt(b, ib);
if (!Character.isDigit(ca) && !Character.isDigit(cb)) {
return bias;
}
if (!Character.isDigit(ca)) {
return -1;
}
if (!Character.isDigit(cb)) {
return +1;
}
if (ca == 0 && cb == 0) {
return bias;
}
if (bias == 0) {
if (ca < cb) {
bias = -1;
} else if (ca > cb) {
bias = +1;
}
}
}
}
public int compare(Object o1, Object o2) {
String a = o1.toString();
String b = o2.toString();
int ia = 0, ib = 0;
int nza = 0, nzb = 0;
char ca, cb;
while (true) {
// Only count the number of zeroes leading the last number compared
nza = nzb = 0;
ca = charAt(a, ia);
cb = charAt(b, ib);
// skip over leading spaces or zeros
while (Character.isSpaceChar(ca) || ca == '0') {
if (ca == '0') {
nza++;
} else {
// Only count consecutive zeroes
nza = 0;
}
ca = charAt(a, ++ia);
}
while (Character.isSpaceChar(cb) || cb == '0') {
if (cb == '0') {
nzb++;
} else {
// Only count consecutive zeroes
nzb = 0;
}
cb = charAt(b, ++ib);
}
// Process run of digits
if (Character.isDigit(ca) && Character.isDigit(cb)) {
int bias = compareRight(a.substring(ia), b.substring(ib));
if (bias != 0) {
return bias;
}
}
if (ca == 0 && cb == 0) {
// The strings compare the same. Perhaps the caller
// will want to call strcmp to break the tie.
return nza - nzb;
}
if (ca < cb) {
return -1;
}
if (ca > cb) {
return +1;
}
++ia;
++ib;
}
}
static char charAt(String s, int i) {
return i >= s.length() ? 0 : s.charAt(i);
}
}